Consider again the family of solutions to .

MATHEMATICS · Multi-part · AP · Calculus AB · Differential Equations · Differential Equations

Problem

Consider again the family of solutions y=Cekxy=C e^{k x} to dydx=ky\dfrac{dy}{dx}=k y. (i) Explain the difference between a general solution and a particular solution of a differential equation, illustrating your answer with y=Cekxy=C e^{k x}. (ii) Describe, without calculation, how the shape of the graph of y=Cekxy=C e^{k x} changes when: (a) kk is positive, (b) kk is negative. Comment on the roles played by kk and CC. (iii) A student claims that the graph of y=Cekxy=C e^{k x} can cross the xx-axis for some choice of CC. Do you agree? Justify your answer.

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