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The molar concentration of required to precipitate for mole of in 500 mL is
CHEMISTRY · Subjective · AP · Chemistry · Equilibrium · Equilibrium
Problem
The molar concentration of
SO
4
2
−
\text{SO}_4^{2-}
SO
4
2
−
required to precipitate
RaSO
4
\text{RaSO}_4
RaSO
4
for
2
×
10
−
4
2 \times 10^{-4}
2
×
1
0
−
4
mole of
Ra
2
+
\text{Ra}^{2+}
Ra
2
+
in 500 mL is
10
−
a
M
10^{-a} M
1
0
−
a
M
. If
K
s
p
K_{sp}
K
s
p
of
RaSO
4
\text{RaSO}_4
RaSO
4
is
4
×
10
−
11
4 \times 10^{-11}
4
×
1
0
−
11
then value of
a
a
a
is.....
Related theory
Equilibrium
Chemical Equilibrium
Solubility product
Solubility Equilibria
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