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The order of magnitude of the density of a uranium nucleus is
PHYSICS · Single correct · CBSE · Physics · Nuclei · Nuclei
Problem The order of magnitude of the density of a uranium nucleus is, given m p = 1.67 × 10 − 27 kg m_p=1.67\times10^{-27}\text{ kg} m p = 1.67 × 1 0 − 27 kg ,
(1) 10 20 kg m − 3 10^{20}\text{ kg m}^{-3} 1 0 20 kg m − 3
(2) 10 17 kg m − 3 10^{17}\text{ kg m}^{-3} 1 0 17 kg m − 3
(3) 10 14 kg m − 3 10^{14}\text{ kg m}^{-3} 1 0 14 kg m − 3
(4) 10 11 kg m − 3 10^{11}\text{ kg m}^{-3} 1 0 11 kg m − 3
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