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The value of is equal to
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
The value of
∫
0
π
/
4
log
(
1
+
tan
θ
)
d
θ
\int_0^{\pi/4}\log(1+\tan\theta)\,d\theta
∫
0
π
/4
lo
g
(
1
+
tan
θ
)
d
θ
is equal to (1)
π
2
log
2
\frac{\pi}{2}\log2
2
π
lo
g
2
(2)
−
π
4
log
2
-\frac{\pi}{4}\log2
−
4
π
lo
g
2
(3)
π
8
log
2
\frac{\pi}{8}\log2
8
π
lo
g
2
(4) None of these
Related theory
Integration Techniques
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Integrals
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