In the , is the mid-point of , is a point on , such that . is a point on the side…

MATHEMATICS · Single correct · CBSE · Mathematics · Vector Algebra · Vector Algebra

Problem

In the ΔOAB\Delta OAB , MM is the mid-point of ABAB , CC is a point on OMOM , such that 2OC=CM2OC = CM . XX is a point on the side OBOB such that OX=2XBOX = 2XB . The line XCXC is produced to meet OAOA in YY . Then, OYYA\frac{OY}{YA} is equal to (1) 73\frac{7}{3} (2) 27\frac{2}{7} (3) 32\frac{3}{2} (4) 25\frac{2}{5}

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