An electron has velocity

PHYSICS · Multi-part · CBSE · Physics · Moving Charges and Magnetism · Moving Charges and Magnetism

Problem

An electron has velocity v=(2.0×106 m s−1)i^+(3.0×106 m s−1)j^\mathbf{v}=(2.0\times10^6\,\text{m s}^{-1})\hat{\mathbf{i}}+(3.0\times10^6\,\text{m s}^{-1})\hat{\mathbf{j}}. The magnetic field in the region is B=(0.030 T)i^−(0.15 T)j^\mathbf{B}=(0.030\,\text{T})\hat{\mathbf{i}}-(0.15\,\text{T})\hat{\mathbf{j}}. (1) Find the force on the electron. (2) Repeat the calculation for a proton having the same velocity.

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