A hot beverage cools on a countertop

MATHEMATICS · Multi-part · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

A hot beverage cools on a countertop. Its temperature TT (in degrees Celsius) for 0 min≤t≤10 min0\text{ min} \le t \le 10\text{ min} satisfies T′(t)=k(t)T'(t)=k(t), where the cooling/heating rate kk (in °C/min^\text{°C/min}) is given by k(t)={−3e−0.5t+0.5,0≤t<4,2,4≤t<6,−1.5sin⁡(π2(t−6)),6≤t≤10.k(t)=\begin{cases} -3e^{-0.5t}+0.5, & 0\le t<4,\\ 2, & 4\le t<6,\\ -1.5\sin\bigl(\tfrac{\pi}{2}(t-6)\bigr), & 6\le t\le 10. \end{cases} At t=0t=0 the beverage is at 80∘C80^{\circ}\text{C}. (1) Part 1: (a) Solve k(t)=0k(t)=0 on 0≤t≤100\le t\le 10 to identify every time at which the temperature is momentarily not changing. (2) Part 2: (b) Write an expression for T(10)−T(0)T(10)-T(0) as a sum of definite integrals, splitting at every time you found in part (a) and at each point where kk changes its defining formula. (3) Part 3: (c) Evaluate the integrals from part (b) to determine the temperature of the beverage at t=10t=10 minutes. Express exact values; do not approximate. (4) Part 4: (d) The beverage is considered ready to drink when its temperature first drops to 65∘C65^{\circ}\text{C}. Use the Fundamental Theorem of Calculus and appropriate reasoning to show that this occurs at a time tt satisfying 4<t<64<t<6. Then, using one additional definite integral you set up, determine the value of tt to the nearest tenth of a minute.

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