A student asserts that the function is a solution to the differential equation on the…

MATHEMATICS · Single correct · CBSE · Mathematics · Differential Equations · Differential Equations

Problem

A student asserts that the function y=ln⁡∣x∣y=\ln|x| is a solution to the differential equation dydx=1x\dfrac{dy}{dx}=\dfrac{1}{x} on the domain x≠0x\neq0. Which of the following best explains why the assertion is incomplete? (a) Because ln⁡∣x∣\ln|x| satisfies dydx=1x\dfrac{dy}{dx}=\dfrac{1}{x} only for x>0x>0; for x<0x<0 its derivative is −1x-\dfrac{1}{x}. (b) A multiplicative constant should appear, so the general solution is y=Cln⁡∣x∣y=C\ln|x|. (c) A constant of integration must be included, so the most general solution is y=ln⁡∣x∣+Cy=\ln|x|+C. (d) The derivative of ln⁡∣x∣\ln|x| is 1x2\dfrac{1}{x^{2}}, not 1x\dfrac{1}{x}.

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