A simple pendulum keeps accurate time at a physics laboratory situated at sea level…

PHYSICS · Multi-part · AP · Physics C: Mechanics · Oscillations · Oscillations

Problem

A simple pendulum keeps accurate time at a physics laboratory situated at sea level where the acceleration due to gravity is 9.80 m s−29.80\,\text{m s}^{-2}. The same pendulum is later taken to an observatory located on a hill top where the local value of gg is 9.76 m s−29.76\,\text{m s}^{-2}. (a) Without performing any numerical calculation, state whether the time period of the pendulum will increase, decrease, or remain unchanged at the hill top. Give a concise reason for your answer. (b) Show that the ratio of the new time period ThillT_{\text{hill}} to the original time period TseaT_{\text{sea}} can be expressed as 9.809.76\sqrt{\dfrac{9.80}{9.76}}. (c) A pendulum clock based on this bob is carried to the hill top and allowed to run for 24 h24\,\text{h} according to its own dial. Will the clock gain time, lose time, or remain correct relative to a standard clock kept at sea level? Justify quantitatively without converting the square-root expression into a decimal.

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