Consider the fission process ^ 239 _ 94 Pu + ^ 1 _ 0 n ; ; ^ 96 _ 38 Sr +^ 140 _ 54…

PHYSICS · Multi-part · A Level · Physics · Nuclear physics · Nuclear physics

Problem

Consider the fission process 94239Pu+01n  →  3896Sr+54140Xe+3 01n.^{239}_{94}\mathrm{Pu}+ ^{1}_{0}\mathrm n \;\rightarrow\; ^{96}_{38}\mathrm{Sr}+^{140}_{54}\mathrm{Xe}+ 3\,^{1}_{0}\mathrm n. The atomic masses are: 94239Pu=239.052163 u^{239}_{94}\mathrm{Pu}=239.052163\,\text{u}, 3896Sr=95.921749 u^{96}_{38}\mathrm{Sr}=95.921749\,\text{u}, 54140Xe=139.921610 u^{140}_{54}\mathrm{Xe}=139.921610\,\text{u}, 01n=1.008665 u^{1}_{0}\mathrm n = 1.008665\,\text{u}. Take 1 u=931.5 MeV1\,\text{u}=931.5\,\text{MeV} and 1 kW h=3.6×106 J1\,\text{kW\,h}=3.6\times10^{6}\,\text{J}. (i) Calculate the mass defect for a single fission event (in u). (ii) Determine the energy released per fission (in MeV). (iii) Compute the total energy liberated if 1.0 kg1.0\,\text{kg} of 239Pu^{239}\mathrm{Pu} undergoes complete fission. Give your answer in joules. (iv) Express the result of part (iii) in kilowatt–hours (kW h).

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