Consider the fission process
94239Pu+01n→3896Sr+54140Xe+301n.
The atomic masses are:
94239Pu=239.052163u,
3896Sr=95.921749u,
54140Xe=139.921610u,
01n=1.008665u.
Take 1u=931.5MeV and 1kWh=3.6×106J.
(i) Calculate the mass defect for a single fission event (in u).
(ii) Determine the energy released per fission (in MeV).
(iii) Compute the total energy liberated if 1.0kg of 239Pu undergoes complete fission. Give your answer in joules.
(iv) Express the result of part (iii) in kilowatt–hours (kW h).