Prove that for any acute angle , (90^ - ) (90^ - ) + (90^ - ) (90^ - ) = , .

MATHEMATICS · Subjective · CBSE · Mathematics · Introduction to Trigonometry · Introduction to Trigonometry

Problem

Prove that for any acute angle θ\theta, sin⁡(90∘−θ)cos⁡(90∘−θ)+cos⁡(90∘−θ)sin⁡(90∘−θ)=csc⁡θ sec⁡θ.\frac{\sin(90^\circ - \theta)}{\cos(90^\circ - \theta)} + \frac{\cos(90^\circ - \theta)}{\sin(90^\circ - \theta)} = \csc \theta\, \sec \theta.

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