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The enthalpy of combustion of propane,
CHEMISTRY · Subjective · A Level · Chemistry · Energetics · Energetics
Problem
The enthalpy of combustion of propane,
C
3
H
8
(
g
)
C_3H_8(g)
C
3
H
8
(
g
)
, is
Δ
H
=
−
2220
kJ mol
−
1
\Delta H = -2220\,\text{kJ mol}^{-1}
Δ
H
=
−
2220
kJ mol
−
1
. Would burning
0.850
mol
0.850\,\text{mol}
0.850
mol
of propane release enough energy to melt
5.0
kg
5.0\,\text{kg}
5.0
kg
of ice at
0
∘
C
0\,^\circ\text{C}
0
∘
C
(
Δ
H
fus
=
6.02
kJ mol
−
1
\Delta H_{\text{fus}} = 6.02\,\text{kJ mol}^{-1}
Δ
H
fus
=
6.02
kJ mol
−
1
)? Support your answer with a brief calculation.
Related theory
Calorimetry
Thermodynamics
Types of enthalpy
Enthalpy Changes of Reactions
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