CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals

Problem

Determine ∫x2cos⁡3x dx\displaystyle \int x^{2}\cos 3x\,dx. (a) 13x2cos⁡3x+29xsin⁡3x−227cos⁡3x+C\dfrac{1}{3}x^{2}\cos 3x+\dfrac{2}{9}x\sin 3x-\dfrac{2}{27}\cos 3x+C (b) 13x2sin⁡3x+29xcos⁡3x−227sin⁡3x+C\dfrac{1}{3}x^{2}\sin 3x+\dfrac{2}{9}x\cos 3x-\dfrac{2}{27}\sin 3x+C (c) 13x2sin⁡3x−29xcos⁡3x+227sin⁡3x+C\dfrac{1}{3}x^{2}\sin 3x-\dfrac{2}{9}x\cos 3x+\dfrac{2}{27}\sin 3x+C (d) 13x2sin⁡3x−23xcos⁡3x+29sin⁡3x+C\dfrac{1}{3}x^{2}\sin 3x-\dfrac{2}{3}x\cos 3x+\dfrac{2}{9}\sin 3x+C

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