For the equilibrium ( G ^ _ N _2 O _4 )_ 298 K = 100 kJ mol ^ -1 and ( G ^ _ NO _2 )_…

CHEMISTRY · Multi-part · A Level · Chemistry · Thermodynamics · Thermodynamics

Problem

For the equilibrium

\text{N}_2\text{O}_4 \rightleftharpoons 2\text{NO}_2

(\text{G}^\circ_{\text{N}_2\text{O}_4})_{298\text{K}} = 100 \text{ kJ mol}^{-1} \text{ and } (\text{G}^\circ_{\text{NO}_2})_{298} = 50 \text{ kJ mol}^{-1}

(i) When 5 mole/litre of each is taken, calculate the value of

\Delta G

for the reaction at

298 \text{ K}

. (ii) Find the direction of reaction and concentration at equilibrium (IIT 2004)