A population of fish in a closed pond evolves according to the differential equation…

MATHEMATICS · Multi-part · AP · Calculus BC · Differential Equations · Differential Equations

Problem

A population P(t)P(t) of fish in a closed pond evolves according to the differential equation dPdt=κP(1−P500),κ>0,\frac{dP}{dt}=\kappa P\Bigl(1-\frac{P}{500}\Bigr), \quad \kappa>0, where tt is measured in months and PP in fish. At time t=0t=0 the population is 350350 fish. After 66 months the population has risen to 400400 fish. (a) Determine the value of the constant κ\kappa. Express κ\kappa exactly. (b) Find a formula for P(t)P(t) that satisfies the given conditions. (c) According to your model, how long in months will it take the population to reach 450450 fish? Express your answer to the nearest tenth of a month. (d) Describe the limiting behavior of P(t)P(t) as t→∞t\to\infty and provide a brief justification based on your solution.

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