CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals

Problem

11. ∫x2−8x+7dx\int \sqrt{x^{2}-8 x+7} d x is equal to (A) 12(x−4)x2−8x+7+9log⁡∣x−4+x2−8x+7∣+C\frac{1}{2}(x-4) \sqrt{x^{2}-8 x+7}+9 \log \left|x-4+\sqrt{x^{2}-8 x+7}\right|+\mathrm{C} (B) 12(x+4)x2−8x+7+9log⁡∣x+4+x2−8x+7∣+C\frac{1}{2}(x+4) \sqrt{x^{2}-8 x+7}+9 \log \left|x+4+\sqrt{x^{2}-8 x+7}\right|+\mathrm{C} (C) 12(x−4)x2−8x+7−32log⁡∣x−4+x2−8x+7∣+C\frac{1}{2}(x-4) \sqrt{x^{2}-8 x+7}-3 \sqrt{2} \log \left|x-4+\sqrt{x^{2}-8 x+7}\right|+\mathrm{C} (D) 12(x−4)x2−8x+7−92log⁡∣x−4+x2−8x+7∣+C\frac{1}{2}(x-4) \sqrt{x^{2}-8 x+7}-\frac{9}{2} \log \left|x-4+\sqrt{x^{2}-8 x+7}\right|+\mathrm{C}

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