The electric field of a plane electromagnetic wave is given by E = E_0 i + j 2 (kz + t) At

PHYSICS · Single correct · A Level · Physics · Fields and their consequences · Fields and their consequences

Problem

The electric field of a plane electromagnetic wave is given byE⃗=E0i^+j^2cos⁡(kz+ωt)\vec{E} = E_0 \frac{\hat{i} + \hat{j}}{\sqrt{2}} \cos(kz + \omega t)At t=0t = 0 , a positively charged particle is at the point (x,y,z)=(0,0,πk)(x, y, z) = \left(0, 0, \frac{\pi}{k}\right) . If its instantaneous velocity at (t=0)(t=0)is v0k^v_0 \hat{k} , the force acting on it due to the wave is: (1) parallel to i^+j^2\frac{\hat{i} + \hat{j}}{\sqrt{2}} (2) zero (3) antiparallel to i^+j^2\frac{\hat{i} + \hat{j}}{\sqrt{2}} (4) parallel to k^\hat{k}

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