A function is continuous on and satisfies where for
MATHEMATICS · Single correct · AP · Calculus AB · Integration and Accumulation of Change · Integration and Accumulation of Change
Problem
A function h is continuous on [0,7] and satisfies
∫03h(t)dt=5and∫37∣h(t)∣dt=6,
where h(t)<0 for 3≤t≤7. What is the value of ∫07h(t)dt?
(a) 11
(b) −11
(c) −1
(d) 1