Let h and k be continuous functions on the interval 1≤x≤5 with h(x)≥k(x) for every x in that interval. The region between the graphs of y=h(x) and y=k(x) from x=1 to x=5 has area 10 square units.
Define new functions p and q by p(x)=3h(x) and q(x)=3k(x)−4 for 1≤x≤5.
(a) Explain why ∫15(h(x)−k(x))dx=10. State any properties of definite integrals you use.
(b) Without computing any antiderivatives, determine the exact value of ∫15(p(x)−q(x))dx. Show all reasoning steps.
(c) Evaluate ∫51(p(x)−q(x))dx and indicate whether the result represents a positive, negative, or zero quantity. Justify your answer.