Two metabolic routes convert precursor Y to product X

CHEMISTRY · Single correct · AP · Chemistry · Thermodynamics and Electrochemistry · Thermodynamics and Electrochemistry

Problem

Two metabolic routes convert precursor Y to product X, an otherwise unfavorable step with ΔG∘=+85 kJ mol−1\Delta G^{\circ}=+85\,\text{kJ}\,\text{mol}^{-1}. • Pathway A couples the step to the hydrolysis of 2 ATP and 1 GTP. • Pathway B couples the step to the hydrolysis of 4 ATP. Standard free energies of hydrolysis are ΔG∘(ATP)=−30.5 kJ mol−1\Delta G^{\circ}(\text{ATP})=-30.5\,\text{kJ}\,\text{mol}^{-1} and ΔG∘(GTP)=−31.5 kJ mol−1\Delta G^{\circ}(\text{GTP})=-31.5\,\text{kJ}\,\text{mol}^{-1}. Which statement about the energetic efficiency of the two pathways is most accurate? (a) Pathway B is more efficient because the larger negative overall free energy change (about −37 kJ mol−1-37\,\text{kJ mol}^{-1}) drives the reaction further. (b) Both pathways are equally efficient because, after accounting for stoichiometry, each hydrolyzes three high-energy phosphate bonds. (c) Pathway A is more efficient because it supplies only a small excess free energy (about −7.5 kJ mol−1-7.5\,\text{kJ mol}^{-1}) beyond what is needed to drive the reaction. (d) Pathway A is less efficient because its overall standard free energy change is positive (about +7.5 kJ mol−1+7.5\,\text{kJ mol}^{-1}), so the reaction would still require input of energy.

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