PHYSICS · Single correct · A Level · Physics · Nuclear physics · Nuclear physics
Problem
For the fusion reaction
12H+13H→24He+01n, calculate the energy released per reaction event in MeV.
Atomic masses:
12H=2.0141u13H=3.0160u24He=4.0026u01n=1.0087u
Take 1u=931.5MeV/c2.
(a) 14.0MeV
(b) 1.76MeV
(c) 17.6MeV
(d) 10.4MeV