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, then is equal…
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
1
−
7
cos
2
x
sin
7
x
cos
2
x
d
x
=
f
(
x
)
(
sin
x
)
7
+
C
\int\frac{1-7\cos^2x}{\sin^7x\cos^2x}\,dx=\frac{f(x)}{(\sin x)^7}+C
∫
s
i
n
7
x
c
o
s
2
x
1
−
7
c
o
s
2
x
d
x
=
(
s
i
n
x
)
7
f
(
x
)
+
C
, then
f
(
x
)
f(x)
f
(
x
)
is equal to (1)
sin
x
\sin x
sin
x
(2)
cos
x
\cos x
cos
x
(3)
tan
x
\tan x
tan
x
(4)
cot
x
\cot x
cot
x
Related theory
Integration Techniques
Standard trigonometric integrals
Integration using trigonometric identities
Integrals
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