When photon of energy 4.25 eV strikes the surface

PHYSICS · Single correct · A Level · Physics · Particles and radiation · Particles and radiation

Problem

When photon of energy 4.25 eV strikes the surface, the ejected electron has maximum kinetic energy TAT_A expressed in eV and de Broglie wavelength λA\lambda_A. The maximum kinetic energy of photoelectrons liberated by another metal BB by photons of 4.70 eV is TBT_B (TB=TA−1.5T_B = T_A - 1.5 eV). If de Broglie wavelength of the electron is λB\lambda_B (λB=2λA\lambda_B = 2\lambda_A), then which is not correct? (1) work function of AA is 2.25 eV (2) TB=0.5T_B = 0.5 eV (3) work function of BB is 1.20 eV (4) TA=2.0T_A = 2.0 eV

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