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The equation of the line which passes through and perpendicular to the line is -
MATHEMATICS · Single correct · CBSE · Mathematics · Straight Lines · Straight Lines
Problem The equation of the line which passes through ( a cos 3 θ , a sin 3 θ ) (a \cos^3 \theta, a \sin^3 \theta) ( a cos 3 θ , a sin 3 θ ) and perpendicular to the line x sec θ + y cosec θ = a x \sec \theta + y \operatorname{cosec} \theta = a x sec θ + y cosec θ = a is -
(1) (A) x cos θ + y sin θ = 2 a cos 2 θ x \cos \theta + y \sin \theta = 2a \cos 2\theta x cos θ + y sin θ = 2 a cos 2 θ
(2) (B) x sin θ − y cos θ = 2 a sin 2 θ x \sin \theta - y \cos \theta = 2a \sin 2\theta x sin θ − y cos θ = 2 a sin 2 θ
(3) (D) x cos θ − y sin θ = a cos 2 θ x \cos \theta - y \sin \theta = a \cos 2\theta x cos θ − y sin θ = a cos 2 θ
(4) (C) x sin θ + y cos θ = 2 a cos 2 θ x \sin \theta + y \cos \theta = 2a \cos 2\theta x sin θ + y cos θ = 2 a cos 2 θ
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