In a molecular-beam experiment

CHEMISTRY · Multi-part · AP · Chemistry · Properties of Substances and Mixtures · Properties of Substances and Mixtures

Problem

In a molecular-beam experiment, a collimated stream of hydrogen molecules (H2\text{H}_2) passes through a small aperture. A detector records the time of flight of molecules over a fixed distance, allowing the experimenters to determine the molecules’ root-mean-square speed. At 280 K280\,\text{K} the measured vrmsv_{\text{rms}} is 1.60×103 m s−11.60 \times 10^3\,\text{m s}^{-1}. The experiment is then repeated at 560 K560\,\text{K}. Later, the same apparatus is used with an unknown diatomic gas (assumed ideal) at 280 K280\,\text{K}. The detector reports a vrmsv_{\text{rms}} equal to the value previously observed for hydrogen at 560 K560\,\text{K}. (The molar mass of H2\text{H}_2 is 2.0 g mol−12.0\,\text{g mol}^{-1}. Universal gas constant R=8.31 J mol−1 K−1R = 8.31\,\text{J mol}^{-1}\,\text{K}^{-1}.) (a) Derive an expression for the ratio of the root-mean-square speeds of the same gas at two different absolute temperatures. (b) Using your result from part (a), calculate the expected vrmsv_{\text{rms}} of hydrogen molecules at 560 K560\,\text{K}. (c) Determine the molar mass of the unknown diatomic gas, given that its vrmsv_{\text{rms}} at 280 K280\,\text{K} equals the value obtained in part (b). (d) The rate at which a gas effuses through a small opening is proportional to its vrmsv_{\text{rms}}. Explain qualitatively how the effusion rate of the unknown gas at 280 K280\,\text{K} compares with that of hydrogen at the same temperature.

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