The isotopes and are often used as reference points in discussions of nuclear stability

PHYSICS · Subjective · AP · Physics 2: Algebra-based · Modern Physics · Modern Physics

Problem

The isotopes 56 ⁣Fe^{56}\!\text{Fe} and 238 ⁣U^{238}\!\text{U} are often used as reference points in discussions of nuclear stability. The following atomic mass data are given: • Mass of a proton =1.007 276 u=1.007\,276\,\text{u} • Mass of a neutron =1.008 665 u=1.008\,665\,\text{u} • Nuclear mass of 56 ⁣Fe=55.934 94 u^{56}\!\text{Fe}=55.934\,94\,\text{u} • Nuclear mass of 238 ⁣U=238.050 79 u^{238}\!\text{U}=238.050\,79\,\text{u} • 1 u1\,\text{u} corresponds to 931.5 MeV931.5\,\text{MeV} of energy. (i) Find the mass defect of one nucleus of 56 ⁣Fe^{56}\!\text{Fe}. (ii) Calculate the total binding energy of the 56 ⁣Fe^{56}\!\text{Fe} nucleus. (iii) Repeat parts (i) and (ii) for one nucleus of 238 ⁣U^{238}\!\text{U}. (iv) Determine the binding energy per nucleon for each isotope and state which of the two nuclei is more tightly bound on a per–nucleon basis. (v) If one mole of 238 ⁣U^{238}\!\text{U} nuclei could be completely broken up into fragments whose average binding energy per nucleon equals the value you obtained for 56 ⁣Fe^{56}\!\text{Fe}, estimate the total energy released in joules. (Take Avogadro number NA=6.022×1023 mol−1N_A = 6.022\times10^{23}\,\text{mol}^{-1}.)

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