For a simple harmonic oscillator whose displacement from equilibrium is modeled by

PHYSICS · Single correct · A Level · Physics · Further mechanics and thermal physics · Further mechanics and thermal physics

Problem

For a simple harmonic oscillator whose displacement from equilibrium is modeled by x=Acos⁡(ωt)x = A\cos(\omega t), which of the following expressions best represents its velocity as a function of time? (a) v(t)=Aωsin⁡(ωt)v(t)=A\omega\sin(\omega t) (b) v(t)=−2Aωsin⁡(ωt)v(t)=-2A\omega\sin(\omega t) (c) v(t)=−Aωsin⁡(ωt)v(t)=-A\omega\sin(\omega t) (d) v(t)=−Aωcos⁡(ωt)v(t)=-A\omega\cos(\omega t)

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