CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Introduction to Trigonometry · Introduction to Trigonometry

Problem

Calculate P=1+tan⁡227∘sec⁡227∘P = \dfrac{1+\tan^2 27^\circ}{\sec^2 27^\circ}. (a) cot⁡227∘\cot^2 27^\circ (b) 11 (c) tan⁡27∘\tan 27^\circ (d) cos⁡27∘\cos 27^\circ

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