A particle moves along a straight line so that its velocity (in meters per second) at…

MATHEMATICS · Multi-part · AP · Calculus AB · Applications of Integration · Applications of Integration

Problem

A particle moves along a straight line so that its velocity (in meters per second) at time tt seconds is v(t)=6t−4v(t)=6t-4 for t≥0t\ge 0. At time t=1t=1, the particle is located 1010 meters to the right of the origin. (a) Find an expression for the particle’s position s(t)s(t), in meters, for t≥0t\ge 0. (b) Determine the time at which the particle crosses the origin (s(t)=0s(t)=0). Provide exact value(s) and justify why your answer satisfies the given initial condition. (c) Compute the total displacement of the particle during the first 44 seconds and interpret your result in the context of the motion.

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