A hiker’s elevation (in meters) is recorded as a function of time measured in hours

MATHEMATICS · Single correct · CBSE · Mathematics · Proportional Reasoning · Proportional Reasoning

Problem

A hiker’s elevation EE (in meters) is recorded as a function of time τ\tau measured in hours. A GPS device displays an instantaneous vertical speed of 1.8 m/s1.8\ \text{m/s}. Assuming the device reports dEdt\dfrac{dE}{dt} where tt is in seconds, what is dEdτ\dfrac{dE}{d\tau} expressed in kilometers per hour? (Use 1 km=1000 m1\ \text{km}=1000\ \text{m} and 1 hr=3600 s1\ \text{hr}=3600\ \text{s}.) (a) 0.648 km/hr0.648\ \text{km/hr} (b) 3.24 km/hr3.24\ \text{km/hr} (c) 6.48 km/hr6.48\ \text{km/hr} (d) 64.8 km/hr64.8\ \text{km/hr}

Related theory

Browse the problem library