A block hangs from a vertical spring

PHYSICS · Single correct · CBSE · Physics · Oscillations · Oscillations

Problem

A block hangs from a vertical spring. Downward is chosen as the positive yy-axis. At one instant the block is y=+0.020 my = +0.020\,\text{m} below equilibrium while moving upward. What is the sign of the spring force on the block at that instant? (a) Positive, because Fs=kyF_s = k y and the displacement yy is positive. (b) Negative, because the spring force acts opposite the displacement, upward toward equilibrium. (c) Zero, because 0.020 m0.020\,\text{m} is very close to equilibrium, so the spring force is essentially negligible. (d) Positive, because the acceleration that slows the upward motion is downward, and downward is the positive yy-direction, so Fs=maF_s=ma is positive.

Related theory

Browse the problem library