The ends of a stretched wire of length are fixed at and

PHYSICS · Single correct · AP · Physics 2: Algebra-based · Waves Sound and Physical Optics · Waves Sound and Physical Optics

Problem

The ends of a stretched wire of length LL are fixed at x=0x = 0 and x=Lx = L. In one experiment, the displacement of the wire is y1=Asin⁡(πx/L)sin⁡ωty_1 = A \sin (\pi x/L) \sin \omega t and energy is E1E_1 and in another experiment its displacement is y2=Asin⁡(2πx/L)sin⁡2ωty_2 = A \sin (2\pi x/L) \sin 2\omega t and energy is E2E_2. Then (1) E2=E1E_2 = E_1 (2) E2=2E1E_2 = 2E_1 (3) E2=4E1E_2 = 4E_1 (4) E2=16E1E_2 = 16E_1

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