In a particular fission event the compound nucleus 236U splits according to
236U→90Sr+144Xe+21n.
(i) Using the atomic masses 236U=236.0456u, 90Sr=89.9077u, 144Xe=143.9229u and 1n=1.00866u, calculate the total energy Q released in the fission. Take 1u=931.5MeV/c2.
(ii) Experimental measurements show that 2% of the energy Q appears as the combined kinetic energy of the two emitted neutrons. Find the average kinetic energy of each neutron in \text{MeV}.
(iii) The remaining 98% of Q appears as kinetic energy of the two fission fragments. Assuming that the fragments share this energy inversely in proportion to their masses, calculate the kinetic energy received by the 90Sr and 144Xe nuclei separately (in \text{MeV}).