A thermal neutron is captured by a 92235U nucleus leading to fission as shown:
92235U+01n⟶56141Ba+3692Kr+301n
Given atomic masses (in u): 92235U=235.043924, 56141Ba=140.914411, 3692Kr=91.926156, neutron =1.008665.
Use 1u=931.5MeV/c2 and 1MeV=1.6×10−13J.
Answer the following.
(i) Calculate the total rest mass of the products and of the reactants in atomic mass units.
(ii) Determine the Q-value of the fission reaction in MeV.
(iii) Convert the energy obtained in part (ii) to joules.
(iv) How much energy is released when 1.0kg of 92235U completely undergoes this fission reaction? (Avogadro number NA=6.02×1023mol−1).