The potential energy associated with a particle moving along the -axis is V(x)=8x^ 2…

PHYSICS · Multi-part · CBSE · Physics · Work, Energy and Power · Work, Energy and Power

Problem

The potential energy associated with a 0.50 kg0.50\,\text{kg} particle moving along the xx-axis is V(x)=8x2  J  (x in metres).V(x)=8x^{2}\;\text{J} \;(x \text{ in metres}). The particle is released from rest at x=0.20 mx=0.20\,\text{m}. (i) Calculate the total mechanical energy of the particle at the instant of release. (ii) Find its speed when it reaches x=0.10 mx = 0.10\,\text{m}. (iii) Determine the maximum distance from the origin the particle can reach during its subsequent motion and explain your reasoning briefly.

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