For a particle the potential energy varies with position as (with in metres)

PHYSICS · Single correct · CBSE · Physics · Work, Energy and Power · Work, Energy and Power

Problem

For a 0.5 kg0.5\,\text{kg} particle the potential energy varies with position as V(x)=4x2 JV(x)=4x^{2}\,\text{J} (with xx in metres). If the particle is released from rest at x=0.25 mx=0.25\,\text{m}, what is the magnitude of its initial acceleration? (a) 8 m s−28\,\text{m\,s}^{-2} (b) 4 m s−24\,\text{m\,s}^{-2} (c) 2 m s−22\,\text{m\,s}^{-2} (d) 16 m s−216\,\text{m\,s}^{-2}

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