Light of frequency produces a stopping potential of for a metal

PHYSICS · Single correct · A Level · Physics · Particles and radiation · Particles and radiation

Problem

Light of frequency 6.0×1014 Hz6.0\times10^{14}\,\text{Hz} produces a stopping potential of 0.7 V0.7\,\text{V} for a metal. When the frequency is increased to 9.0×1014 Hz9.0\times10^{14}\,\text{Hz}, the stopping potential becomes 2.2 V2.2\,\text{V}. Calculate Planck’s constant hh. (Take e=1.6×10−19 Ce = 1.6\times10^{-19}\,\text{C}.) (a) 1.2×10−33 J s1.2\times10^{-33}\,\text{J\,s} (b) 6.6×10−34 J s6.6\times10^{-34}\,\text{J\,s} (c) 8.0×10−34 J s8.0\times10^{-34}\,\text{J\,s} (d) 3.7×10−34 J s3.7\times10^{-34}\,\text{J\,s}

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