A crystal carries electron magnetic moments on fixed sites

PHYSICS · Multi-part · Fermi University Physics · Thermal, Statistical & Complex Systems · Electricity, Magnetism & Electromagnetism · Statistical foundations and the equilibrium ensembles

Thermal Physics, Ch Two-level systems, paramagnets and the Einstein solid

Problem

A crystal carries N=4.0×1022N = 4.0\times10^{22} electron magnetic moments on fixed sites, each of magnitude μm=9.27×10−24 J T−1\mu_{\rm m} = 9.27\times10^{-24}\,\mathrm{J\,T^{-1}}, with two allowed orientations in an applied field B=2.0 TB = 2.0\,\mathrm{T}: energy −μmB-\mu_{\rm m}B aligned and +μmB+\mu_{\rm m}B anti-aligned. A measurement finds 7070 per cent of the moments aligned with the field and 3030 per cent anti-aligned. The moments are weakly coupled to the lattice, and the field energy is excluded from UU. Recall from Chapter 11 that the multiplicity of such a set is Ω=N!/(N↑! N↓!)\Omega = N!/(N_\uparrow!\,N_\downarrow!), where N↑N_\uparrow and N↓N_\downarrow are the numbers aligned and anti-aligned, and that S=kBln⁡ΩS = k_B\ln\Omega; recall from Chapter 11 that qq quanta shared among NoscN_{\rm osc} oscillators can be arranged in Ω=(q+Nosc−1)!/[q! (Nosc−1)!]\Omega = (q+N_{\rm osc}-1)!/\left[q!\,(N_{\rm osc}-1)!\right] ways. ((a)) Use the multiplicity with Stirling's approximation to find the entropy of the set of moments, per moment in units of kBk_B and in total. ((b)) Find the temperature that fits these populations through the Boltzmann factor, then compute the entropy again from the free energy F=−NkBTln⁡Z1F = -Nk_BT\ln Z_1 of this chapter, and show the two routes agree. State the sign of TT and say why. ((c)) A copper crystal is modelled as an Einstein solid with θE=240 K\theta_E = 240\,\mathrm{K}; Nosc=3.0×1022N_{\rm osc} = 3.0\times10^{22} of its oscillators share q=7.5×1021q = 7.5\times10^{21} quanta. From the Chapter 11 count, with U=qhνU = qh\nu and 1/T=(∂S/∂U)N1/T = (\partial S/\partial U)_{N}, find the temperature of the crystal. Then compute the mean energy per oscillator from this chapter's partition function at that temperature and show it equals qhν/Noscqh\nu/N_{\rm osc}.

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