Torsional Strain and the Origin of the Ethane Barrier
Spin the two halves of an ethane molecule relative to each other. The energy rises and falls in a gentle wave. This wave is roughly 12 kJ/mol, occurring six times per full turn. This is the smallest, purest example of a conformational energy landscape in all of chemistry. For decades chemists explained it with a story about clashing hydrogen atoms bumping into each other. That story is intuitive and quantitatively convenient. But modern quantum-chemical analysis shows it is not the real reason the barrier exists. The rotational barrier in ethane matters far beyond ethane itself. It is the seed from which the whole discipline of conformational analysis grows. The preference for staggered over eclipsed arrangements sets the default geometry. This applies to every sp³–sp³ bond in every alkane, lipid, protein side chain, and drug molecule. Understanding why staggered ethane is 12.0 kJ/mol more stable than eclipsed ethane matters greatly. It is really understanding why carbon chains adopt the zig-zag shapes they do. It explains why cyclohexane is a chair and not a hexagon. It also explains why rotation about single bonds is fast but not free. The classical explanation invokes steric strain. Eclipsing hydrogens are close enough that their electron clouds repel each other. This is like two people trying to occupy the same seat. This picture is pedagogically useful and gets the sign of the effect right. But modern orbital-based analysis shows otherwise. Natural bond orbital (NBO) decomposition of the ab initio wavefunction reveals a different story. Van der Waals repulsion between eclipsing H atoms is far too small. It is also too weak a function of angle. It cannot generate a 12 kJ/mol barrier with six-fold symmetry. The dominant contribution instead comes from hyperconjugation. This involves donation of electron density from a filled C–H σ bonding orbital on one carbon. That density flows into the empty σ\ antibonding orbital of a C–H bond on the neighboring carbon. This donation is maximized in the staggered conformation. There, the donor σ and acceptor σ\ are anti-periplanar, near-perfectly aligned. The donation vanishes in the eclipsed conformation. There, the same orbitals are nearly orthogonal. The energy difference between "lots of stabilizing donation" and "very little" is the rotational barrier. It is a genuine electronic, quantum-mechanical effect. It is not a classical bumping of billiard balls. This article works through both pictures rigorously. First is the steric/electrostatic story your first course likely gave you. Second is the σ→σ\* hyperconjugative story that modern computational chemistry actually supports. You will see the curved-arrow (donor-orbital-to-acceptor-orbital) mechanism for why staggered wins. You will get a full accounting of the 12 kJ/mol barrier height. Worked examples are included, such as a substituted case: 1,1,2,2-tetrafluoroethane. There, fluorine lone pairs change the calculus dramatically. Finally, you will see the traps that catch students who over-apply the simple steric model.
- Rotating the C–C bond in ethane costs energy: the staggered conformation is a potential-energy minimum, the eclipsed a maximum, threefold-repeating every 120°.
- The barrier height is small: ≈ 12.0 kJ/mol (2.9 kcal/mol), comparable to a hydrogen bond, so rotation at room temperature is extremely fast (~10¹⁰–10¹¹ s⁻¹).
- The traditional explanation — steric (van der Waals) repulsion between eclipsing H···H pairs — gets the right sign but is quantitatively too small and geometrically wrong-shaped to be the main cause.
- The dominant physical origin is hyperconjugation: σ(C–H) → σ\*(C–H) donation across the C–C bond, which is maximal when bonds are anti-periplanar (staggered) and minimal when eclipsed.
- Natural Bond Orbital (NBO) analysis decomposes the rotational energy into steric, electrostatic, and hyperconjugative pieces and finds hyperconjugation dominates, with sterics acting only as a modest reinforcing term.
- This single 12 kJ/mol effect, multiplied along a chain, is the microscopic reason for the anti-preference in Conformations of Butane: Gauche and Anti and for chair puckering in Ring Strain in Cycloalkanes: Baeyer's Model and Reality.
- Key idea: the ethane barrier is not two hydrogens bumping into each other — it is the loss of stabilizing σ→σ\* electron donation when C–H bonds rotate out of anti-periplanar alignment.
Staggered ethane is more stable than eclipsed ethane primarily because staggered geometry aligns each filled C–H σ orbital anti-periplanar to a C–H σ\ orbital on the adjacent carbon, allowing stabilizing two-electron donation (σ→σ\) that is geometrically forbidden (near-zero overlap) in the eclipsed geometry.
Where this lives today
The ethane barrier is the atomic-scale seed of essentially all conformational chemistry. In drug design, computing accurate torsional energy profiles for rotatable bonds is essential for predicting bioactive conformations and building reliable molecular-mechanics force fields (AMBER, CHARMM, OPLS); these force fields explicitly parameterize torsional terms as Fourier series of exactly the form derived here, with coefficients fit (in modern force-field development) to reproduce quantum-mechanically computed hyperconjugative barriers rather than purely steric estimates. In materials science, the same physics governs rotational barriers about C–C and C–Si bonds in polymer backbones, influencing chain flexibility, glass transition temperatures, and mechanical properties of plastics and elastomers. In structural biology, hyperconjugative preferences for anti-periplanar alignment underlie the preferred backbone and side-chain torsion angles (χ angles) that stabilize specific protein conformations and are tabulated in Ramachandran-adjacent rotamer libraries used in crystallographic refinement and homology modeling. The anomeric effect in carbohydrate chemistry — the preference for an electronegative substituent at the anomeric carbon of a pyranose ring to sit axial rather than equatorial, contrary to naive steric expectation — is mechanistically the same phenomenon as the ethane barrier, generalized: an oxygen lone pair donating into an anti-periplanar σ\(C–X) orbital, exactly analogous to the σ(C–H)→σ\(C–H) donation described here but with a lone pair as donor. This connects directly forward to how substituted alkane chains prefer Conformations of Butane: Gauche and Anti arrangements, and to why cyclohexane rings and other cyclic systems distort away from idealized polygon geometries in Ring Strain in Cycloalkanes: Baeyer's Model and Reality, both of which layer additional steric (1,3-diaxial, gauche-butane) strain on top of this same underlying torsional/hyperconjugative foundation. Modern computational instrumentation — high-level ab initio methods (CCSD(T), MP2) combined with NBO deletion experiments — routinely dissects torsional barriers in exactly the manner outlined in Mechanism 1 for far more complex molecules, from pharmaceutical leads to polymer monomers, making the ethane barrier not a historical curiosity but the calibration standard against which every more complicated torsional analysis is still checked.
Ask the tutor: How does adding a methyl group (as in butane) combine this torsional/hyperconjugative barrier with genuine steric gauche strain to produce the anti/gauche energy difference?
The physical picture
Picture ethane down the C–C axis, exactly as you would draw a Newman projection. In the staggered conformation, each front C–H bond bisects the angle between two back C–H bonds; the H–C–C–H dihedral angles are 60°, 180°, and 300° (≡ −60°) for the three pairs. In the eclipsed conformation, front and back C–H bonds line up directly, with dihedral angles of 0°, 120°, and 240°. The classical (steric) account says: in the eclipsed form, each pair of eclipsing hydrogens sits only about 2.29 Å apart (closer than the sum of their van der Waals radii, ~2.4 Å), producing exchange-repulsion between the electron clouds. Rotating to staggered increases the H···H distance to about 2.55 Å (since staggered H's are gauche-like, not directly aligned), relieving this repulsion. This model correctly predicts that staggered is lower in energy and that the potential has three-fold symmetry (three equivalent staggered minima, three equivalent eclipsed maxima per 360°). But when you compute the actual van der Waals repulsion energy between two H atoms at 2.29 Å using standard nonbonded potentials, you get only a fraction of a kJ/mol per pair — nowhere near enough to build a 12 kJ/mol barrier from three such pairs. The orbital picture explains the missing energy. Each C–H bond has a bonding combination (σ, filled, two electrons, lower energy) and an antibonding combination (σ\, empty, higher energy) built from the carbon sp³ hybrid and the hydrogen 1s orbital. A filled σ(C–H) orbital on one carbon and an empty σ\(C–H) orbital on the neighboring carbon can interact — donating electron density from the filled orbital into the empty one — exactly as a lone pair donates into an antibonding orbital in classic hyperconjugation or anomeric effects. This donation is a second-order perturbative stabilization, and its magnitude depends critically on the dihedral angle between the donor σ bond and the acceptor σ\* bond, because orbital overlap (and hence donation) is maximal when the two are collinear (anti-periplanar, 180°) and minimal when they are orthogonal (90°) or eclipsed (0°, where overlap is small but nonzero due to geometry).
The key geometric fact, made precise below, is that hyperconjugative stabilization from a single donor–acceptor σ/σ\ pair scales with the square of the overlap, which itself scales as where is the dihedral angle between the donor and acceptor bond axes (measuring 180° as perfectly anti-periplanar). Summing over all nine such vicinal σ(C–H)→σ\(C–H) interactions around the C–C bond (three on each side interacting with three on the other, though only the near-anti and near-eclipsed ones matter most) reproduces both the three-fold periodicity and, semi-quantitatively, the magnitude of the real barrier.
The core ideas
The rotational potential energy of ethane as a function of the C–C dihedral angle φ is, to leading order, a pure cosine with three-fold periodicity:
where:
- is the torsional energy at dihedral angle (defining as staggered, as eclipsed),
- is the barrier height, the full energy difference between eclipsed maximum and staggered minimum,
- the factor oscillates between 0 (staggered, ) and 1 (eclipsed, ).
Reading this equation: at (fully eclipsed), , so shifted appropriately — by convention we set the eclipsed conformer as the energy zero and staggered as , or vice versa; either way the difference between maxima and minima is exactly . Experimentally (from microwave and far-infrared torsional spectroscopy of ethane),
The hyperconjugative contribution to this barrier can be estimated from second-order perturbation theory applied to the donor σ(C–H) and acceptor σ\*(C–H) natural bond orbitals. The stabilization energy from one donor–acceptor pair is:
where:
- is the occupation number of the donor σ orbital (2, since it's a filled bond),
- is the off-diagonal Fock (or Kohn–Sham) matrix element coupling donor and acceptor — proportional to their spatial overlap,
- is the energy gap between the antibonding and bonding orbital,
- the minus sign shows this term always lowers energy (donation is always stabilizing).
Because the coupling matrix element is proportional to orbital overlap, and overlap between two σ-type bond orbitals separated by dihedral angle falls off approximately as (with measured from perfect anti-alignment), the stabilization energy — being proportional to the square of the coupling — scales as:
reading: donation is maximal (most negative, most stabilizing) when (perfectly anti-periplanar donor/acceptor pair) and vanishes at (orthogonal, zero overlap by symmetry).
Goal. Show, orbital by orbital, why rotating ethane from eclipsed to staggered turns on stabilizing σ(C–H)→σ\*(C–H) donation, and why this alone predicts a three-fold barrier of the observed order of magnitude.
Step 1: Identify the donor and acceptor orbitals. Each C–H bond in ethane is described (in the natural bond orbital / localized MO picture) by a bonding orbital
and an orthogonal antibonding combination
The bonding orbital is filled (2 electrons); the antibonding orbital is empty and lies several eV higher in energy. Every C–H bond on carbon can act as a donor (, filled) toward every C–H bond on the neighboring carbon acting as an acceptor (, empty), and vice versa. There are nine such vicinal σ→σ\* pathways (3 donors × 3 acceptors) contributing around the C–C axis, though the dominant ones are those closest to anti-periplanar alignment.
Step 2: Evaluate overlap as a function of dihedral angle. The donor σ(C–H) orbital on points along a fixed direction in space (roughly along the tetrahedral C–H axis). The acceptor σ\(C–H) orbital on rotates as the C–C bond rotates. Constructive, sizeable overlap between the back lobe of σ(C–H) (pointing backward through the C–C bond, toward ) and the σ\(C–H) orbital requires the two bonds to be anti-periplanar — dihedral angle 180° between the σ(C–H) bond and the C–H bond whose σ\ is accepting. In a staggered Newman projection, each back C–H bond sits exactly anti to one front C–H bond (dihedral 180°) and gauche (60°) to the other two. In the eclipsed Newman projection, each front C–H sits directly over (dihedral ≈ 0°) one back C–H and gauche-like (120°) to the other two — and a dihedral of 0° is a poor donor–acceptor geometry for σ/σ\ overlap through the intervening C–C bond (the relevant overlap integral is small at both 0° and 90°, and substantial only near 180°).
Step 3: Sum the three dominant interactions and locate the extrema. In the staggered conformer, each of the three back C–H σ orbitals is anti-periplanar (180°) to one specific front C–H σ\ orbital — three "perfect" donor/acceptor alignments simultaneously. This is the geometric reason staggered, not some other angle, is special: it is the unique rotamer (up to the three-fold repeat) that maximizes the number of anti-periplanar σ/σ\ pairs at once. Using per pair and summing the three near-anti pathways (each near measured from the ideal anti geometry) gives a large net stabilization. Rotating away from staggered toward eclipsed continuously misaligns all three pairs simultaneously, monotonically switching off the donation, until at full eclipse (0°) the alignment is poorest and stabilization is smallest.
Step 4: Translate the per-pair energy into the barrier. Natural bond orbital calculations on ethane (Weinhold and coworkers, and many subsequent studies) find that deleting the σ(C–H)→σ\*(C–H) hyperconjugative interactions from the wavefunction (artificially, in the "NBO deletion" computational experiment) removes essentially the entire rotational barrier — replacing it with a barrier of the wrong sign or near zero. Quantitatively, the total hyperconjugative stabilization is calculated to be roughly 10–12 kJ/mol larger in the staggered form than in the eclipsed form, closely matching the full experimental barrier of 12.0 kJ/mol. This is the central mechanistic claim: the barrier is (predominantly) a hyperconjugative energy, not a steric one.
Step 5: Note the steric/electrostatic residual. NBO energy decomposition also isolates a genuine steric (Pauli exchange-repulsion) term and an electrostatic term. Both favor staggered over eclipsed as well (closer H···H contacts in eclipsed do cost some repulsive energy, and there are small electrostatic contributions), but together they are much smaller than the hyperconjugative term and act as a reinforcing minority contribution rather than the main cause. This resolves the apparent conflict between the "textbook steric" story (right sign) and the "real" electronic story (right magnitude and origin): sterics are real but subordinate.
Go deeper · Derivation B · 2 minMechanism 2 — Torsional potential from bond-bond interaction and the shape of E(φ)
Goal. Derive the functional form from the pairwise-interaction idea, and show it reproduces the correct periodicity and symmetry independent of the detailed physical origin (steric or hyperconjugative) of the pairwise term.
Step 1: Set up the three pairwise interactions. Label the three front C–H bonds by azimuthal angle (i = 1,2,3, spaced 120° apart) and the three back C–H bonds by similarly. As the molecule rotates about the C–C axis by dihedral , each front–back "facing pair" has a relative angular offset (a fixed 120°-spaced offset). Each pair contributes an interaction energy depending only on their relative azimuthal separation, whatever its microscopic origin (H···H sterics, or σ/σ\* hyperconjugation, or both).
Step 2: Assume the simplest periodic form for a single pair. By symmetry, must be periodic in with period 360° and must have a single maximum at (bonds eclipsing) and single minimum at (bonds anti) if we consider just one pair rotating in isolation, i.e. to lowest Fourier order:
so that (maximum, eclipsing) and (minimum, anti).
Step 3: Sum over the three symmetric pairs. The three pairs are offset from each other by 120°, so the total torsional energy is
The sum of cosines spaced 120° apart vanishes identically for a linear combination ( for all , a standard trigonometric identity), so a naive first-order sum gives a constant — no barrier at all! This shows that the barrier cannot arise from a single Fourier harmonic per pair; it requires either an anisotropic (non-single-cosine) pairwise potential or, physically, the fact that not all three pairs are equivalent simultaneously in the way assumed. Carrying the pairwise potential to include a second harmonic,
and re-summing over the three 120°-offset pairs, the first-harmonic terms cancel exactly as before, but the second-harmonic terms reinforce, because evaluated at effectively samples angles , which do not cancel when combined with the specific structure of the problem — the physically correct treatment (short-ranged, not purely cosine, potentials, or equivalently a direct symmetry argument) shows that only Fourier components that are multiples of 3 in survive the three-fold averaging. This is why the observed torsional potential is written directly as a single term:
— the lowest-order term compatible with the exact three-fold (C₃) symmetry of the rotor, regardless of whether the underlying microscopic pairwise energy is steric, electrostatic, or hyperconjugative. This is the crucial subtlety: symmetry alone fixes the form of ; only the coefficient carries information about the physical mechanism, and it is the NBO/hyperconjugation analysis (Mechanism 1) that tells us why kJ/mol rather than, say, 2 kJ/mol (pure sterics) or 40 kJ/mol.
Step 4: Extract barrier height and locate extrema. Differentiating,
Setting this to zero gives extrema at — i.e. every 60°, alternating maxima and minima, exactly the eclipsed/staggered alternation observed. The second derivative,
is positive (minimum) at (staggered, since ... check sign carefully: at , , , so — this indicates the convention must be checked against which point is defined as ). Taking as staggered (redefining the phase for convenience, since the physical content — three minima and three maxima 60° apart — is convention-independent) gives as the minimum and as the maximum, confirming the barrier height is exactly from trough to crest.
Worked examples
Example 1 (foundational): Converting the barrier between units and finding the barrier per H···H eclipsing interaction. The experimental barrier is kJ/mol. Convert to kcal/mol and to a per-eclipsing-pair quantity, given that there are three equivalent H···H eclipsing interactions in the fully eclipsed conformer.
If (in the crude, purely additive steric picture) the entire barrier were divided evenly among the three equivalent eclipsing H···H interactions,
This is the number often quoted in introductory courses as "the cost of one eclipsing H–H interaction," roughly 4.0 kJ/mol (about 1.0 kcal/mol) per pair. It is worth being explicit that this is an operational bookkeeping number — useful for predicting barriers in other eclipsed systems by counting interactions — not a direct measurement of van der Waals repulsion at 2.29 Å, which independent nonbonded-potential estimates put far lower (a few tenths of a kJ/mol). The discrepancy between 4.0 kJ/mol "as if steric" and the much smaller true van der Waals contribution is exactly the gap that hyperconjugation fills, as shown in Mechanism 1.
Limiting-case check: as the dihedral angle sweeps continuously from to , from the formula in the core-ideas section must return exactly to its starting value and pass through exactly three maxima and three minima — consistent with the three-fold symmetry of a staggered/eclipsed/staggered/eclipsed... sequence every 60°, which is what the cosine form guarantees by construction.
Example 2 (applied): Estimating the rotational barrier of 1,1,2,2-tetrafluoroethane and explaining the deviation from simple ethane using both models. 1,1,2,2-Tetrafluoroethane (F₂HC–CHF₂) has a measured internal rotation barrier of about 18–20 kJ/mol between its staggered conformers — noticeably higher than plain ethane's 12.0 kJ/mol, even though replacing H with the larger F atom might naively be expected to increase steric repulsion in the eclipsed form dramatically (van der Waals radius of F, ~1.47 Å, is substantially larger than H's ~1.20 Å). If sterics were the whole story, an F···F eclipsing interaction should be dramatically more repulsive than an H···H one, correctly predicting a higher barrier — so far consistent. But the size and pattern of barriers across the halogenated ethanes (F, Cl, Br substitution patterns) do not scale simply with atomic radius; they correlate much better with the number and energy of available σ\(C–F) or σ\(C–H) acceptor orbitals. Fluorine's high electronegativity lowers the energy of the σ\(C–F) orbital (making it a better acceptor, since is smaller in the denominator of the hyperconjugation formula), and simultaneously the C–H bonds are somewhat better donors when attached to a carbon bearing electronegative F substituents (rehybridization increases s-character in the C–H bonds, per Bent's rule, strengthening σ(C–H) as a donor). The result is that σ(C–H)→σ\(C–F) anti-periplanar donation across the C–C bond is stronger than plain σ(C–H)→σ\*(C–H) donation in ethane, mechanistically raising the barrier well beyond what a naive "just bigger atoms, more steric clash" argument would predict on its own. Quantitatively:
This roughly 7 kJ/mol enhancement is understood as arising predominantly from the improved σ(C–H)→σ\(C–F) hyperconjugative pathway (lower-energy σ\ acceptor orbital), not from a doubling of steric bulk — a clean, checkable illustration of why the orbital picture, not the ball-bumping picture, is needed to rationalize real substituent trends.
Example 3 (competition-level): Estimating the population ratio of staggered to eclipsed-like conformations and the implied rotational barrier crossing rate at 298 K, then checking against the observed IR torsional frequency. Given kJ/mol, estimate (a) the equilibrium population ratio of molecules sitting exactly at a staggered minimum versus exactly at an eclipsed maximum using a naive Boltzmann factor (recognizing this is a crude two-state cartoon of a continuous rotor, useful for building intuition about barrier-crossing statistics), and (b) compare the thermal energy at 298 K to to judge whether rotation is "fast" on the NMR/vibrational timescale.
(a) The Boltzmann ratio of populations at the potential maximum versus minimum is
At K, J/(mol·K), so J/mol kJ/mol. Then:
So even at the exact top of the barrier, the population is suppressed by roughly a factor of 126 relative to the bottom of the well — but because is comparable to (not many multiples larger), thermal energy is easily enough to populate the barrier top transiently and the molecule crosses back and forth extremely rapidly; this is not a case (like biphenyl atropisomers with barriers of 100+ kJ/mol) where distinct rotamers could ever be isolated at room temperature.
(b) Comparing directly: (2.48 kJ/mol at 298 K) is about one-fifth of (12.0 kJ/mol) — small enough that thermal population of near-barrier-top geometries is easy and rotation is correspondingly fast, but large enough that the potential well is not "washed out": ethane spends the overwhelming majority of its time near the three staggered minima, consistent with a well-defined equilibrium geometry and with observed torsional vibrational fine structure (the C–C torsional mode is observed near 289 cm⁻¹ in the Raman/IR spectrum of ethane, and standard treatment of this mode as a hindered rotor using the value above reproduces the observed torsional level spacings to good approximation).
Limiting case: as (imagine artificially switching off hyperconjugation and sterics), the exponential ratio , meaning every dihedral angle becomes equally populated — free internal rotation, exactly the qualitative behavior expected if there really were no preference between staggered and eclipsed, confirming the formula's sanity at the trivial limit.
Limiting cases, scope & common traps
| Situation | What happens | Governing idea |
|---|---|---|
| Ethane, room temperature | Fast rotation (~10¹⁰–10¹¹ s⁻¹), staggered strongly preferred but not isolable as separate species | kJ/mol ≈ few ; Boltzmann-fast interconversion |
| (hypothetical) | Free rotation, uniform dihedral population | No stabilizing σ/σ\* alignment preference; degenerate rotor |
| Substituent with low-lying σ\* (e.g., C–F, C–Cl) anti-periplanar to C–H | Barrier increases beyond naive steric prediction | Better hyperconjugative acceptor lowers |
| Substituent lone pair (e.g., C–OH, C–NH₂) available anti-periplanar | Anomeric-like extra stabilization; barrier and preferred rotamer both shift | n(lone pair)→σ\*(C–X) donation, same mechanism family |
| Very bulky substituents (e.g., tert-butyl groups on both carbons) | Steric term becomes comparably large or dominant; simple hyperconjugative picture alone insufficient | Genuine van der Waals/Pauli repulsion competes with electronic term |
| Cold matrix / very low T | Population concentrates almost entirely in staggered wells; barrier crossing effectively frozen out | Boltzmann factor |
The chemist behind it
The rotational barrier of ethane was first inferred not from a single "discoverer" in the Newtonian sense but through a convergence of thermodynamic and spectroscopic evidence in the late 1930s. Its interpretation was substantially reshaped decades later by the development of natural bond orbital theory.
Origins · 1 minFrank Weinhold and how this was discovered
Frank Weinhold, professor at the University of Wisconsin–Madison, developed (with Clark R. Landis and coworkers) the Natural Bond Orbital (NBO) method — a systematic way of transforming delocalized molecular-orbital wavefunctions from ab initio or density-functional calculations into a compact, chemically intuitive set of localized "Lewis-structure-like" orbitals (bonds, lone pairs, and their antibonding/Rydberg complements), together with a rigorous second-order perturbative energy decomposition of donor–acceptor interactions between them. Applying this machinery to ethane in the early 2000s (building on earlier work by Weinhold, Pophristic, and Goodman), Weinhold's group provided the now-standard demonstration that deleting the σ(C–H)↔σ\*(C–H) hyperconjugative interactions from the ethane wavefunction removes essentially the entire rotational barrier, while artificially forcing the molecule to eclipsed geometry without altering these interactions produces almost none of the actual energy penalty from sterics alone — directly overturning the previously dominant purely-steric explanation that had been textbook orthodoxy since the 1930s.
Is the ethane rotational barrier the same thing as "steric strain"?
Not exactly. Classical steric strain — van der Waals repulsion between eclipsing hydrogen atoms — does contribute a small, real, stabilizing preference for staggered geometry, and it correctly predicts the sign of the effect. But quantitative analysis (NBO energy decomposition) shows this steric term is much smaller than the full 12.0 kJ/mol barrier. The dominant contribution is hyperconjugative: σ(C–H)→σ\*(C–H) donation, maximized when bonds are anti-periplanar (staggered) and minimized when eclipsed. Modern usage reserves "torsional strain" as the umbrella term for the whole rotational energy penalty, while recognizing that its microscopic origin is mostly electronic (orbital), not classically steric.
Why is the barrier exactly three-fold periodic, repeating every 120°?
This follows directly from the C₃ symmetry of the ethane rotor: each methyl group has three equivalent C–H bonds arranged 120° apart, so rotating the C–C bond by 120° maps the molecule onto an indistinguishable configuration. Any physically sensible potential energy function for this rotation must therefore be periodic with period 120° (equivalently, expressible as a Fourier series in ), and to leading (dominant) order this series is well-approximated by the single term , which alone already reproduces three equally spaced minima and three equally spaced maxima per full rotation.
How fast does ethane actually rotate at room temperature?
Extremely fast. Because the barrier (12.0 kJ/mol) is only a few times larger than thermal energy (2.48 kJ/mol at 298 K), the Boltzmann factor indicates frequent barrier crossing. Transition-state-theory estimates and direct spectroscopic/dynamical studies place the rotational interconversion rate around – times per second at room temperature — far too fast for NMR or any other common technique to resolve staggered and eclipsed forms as separate, observable species; only a single time-averaged (staggered-dominated) structure is ever detected experimentally.
Does the hyperconjugative explanation mean sterics never matter in conformational analysis?
No — sterics matter enormously in larger, more substituted systems, just not as the dominant term in the unsubstituted ethane barrier specifically. Once you replace hydrogens with bulkier groups (as in Conformations of Butane: Gauche and Anti, where a methyl group replacing hydrogen introduces genuine steric gauche interactions on top of the underlying hyperconjugative torsional preference), classical steric (Pauli exchange) repulsion becomes an increasingly large, sometimes dominant, contribution to the total conformational energy. The lesson of the ethane barrier is not "sterics never matter" but "do not assume sterics are the whole story without checking the orbital-level accounting."
What experimental evidence establishes the 12.0 kJ/mol barrier height, independent of any theoretical model?
The barrier is measured directly from spectroscopy and thermodynamics, independent of any orbital interpretation. Torsional (hindered-rotor) vibrational transitions of ethane appear in the far-infrared and Raman spectrum near 289 cm⁻¹, and fitting the observed spacing of these torsional energy levels to a hindered-rotor Hamiltonian with potential yields kJ/mol. Independently, heat-capacity measurements (originally by Kemp and Pitzer in 1936) showed ethane's measured entropy and heat capacity deviate from the free-rotor prediction in a way consistent with a hindered rotor of comparable barrier height, an early and largely model-independent confirmation.
Why doesn't the classical electrostatic picture (partial charges on H atoms) explain the barrier either?
Electrostatic interactions between the small partial charges on hydrogen atoms in a nonpolar C–H bond are weak and, like simple sterics, contribute only a modest term to the total rotational energy in NBO decomposition — not the dominant one. Because C–H bonds are only weakly polarized (carbon and hydrogen have similar electronegativity), the partial charges involved are small, and Coulombic H···H interactions at the relevant distances (2.3–2.6 Å) are simply too weak in magnitude to generate a 12 kJ/mol effect on their own; they reinforce the hyperconjugative term slightly but are not its origin.
Does this same hyperconjugative mechanism explain the anomeric effect in sugars?
Yes, essentially the same orbital mechanism, generalized. In the anomeric effect, a lone pair on a ring oxygen (rather than a filled C–H σ bond) donates into an anti-periplanar σ\(C–X) orbital at the neighboring anomeric carbon, favoring the axial orientation of an electronegative substituent X (such as an OR or halogen group) against naive steric expectation. This n(O)→σ\(C–X) donation is stronger than the σ(C–H)→σ\*(C–H) donation in ethane because a lone pair is a higher-energy, better donor orbital than a bonding σ orbital, illustrating how the same donor–acceptor framework scales up to explain more dramatic conformational preferences in heteroatom-rich systems.