Units and measurement systems

Every physics law is really a sentence about measurable quantities, and no measurement means anything without a unit to compare it against. Say a rod is "5 metres" long and you are really saying its length is five times a fixed reference length called the metre. That reference has to be well-defined, unchanging, reproducible in any lab, and of a convenient size — otherwise physicists in different countries and different centuries could never agree on a number. This article opens the ISC Class 11 chapter "Physical World and Measurement." It builds the historical unit systems up to SI, the seven SI base units, how derived units are built from them, the standard prefixes from atto to tera, and the special units used for scales far outside everyday experience, from the femtometre inside a nucleus to the parsec between stars.

The core insight

A unit is a fixed, reproducible reference amount; SI fixes seven such references as base units, builds every other unit from them by combination, and uses powers-of-ten prefixes and special named units to keep numbers manageable across scales from 10−15 m10^{-15}\ \text{m} to 1016 m10^{16}\ \text{m} and beyond.

The core idea

What a unit must be. A measurement is always (numerical value) times (unit) — 5 m5\ \text{m} means "5 times the metre." For a unit to be usable across labs and centuries, it must be well-defined, invariable (independent of time, place, or the person defining it), easily reproducible, accessible for comparison, and of convenient size — not so large or small that everyday numbers become unwieldy.

Systems that led to SI. Different eras and regions settled on different base sets before the world agreed on one:

  • CGS — centimetre, gram, second
  • FPS — foot, pound, second
  • MKS — metre, kilogram, second
  • MKSA — metre, kilogram, second, ampere, adding the ampere so electrical quantities had a base
  • SI (Système International d'Unités) — adopted in 1971, the modern extension of MKSA, built on seven independent base units
measured quantity=(numerical value)×(unit)\text{measured quantity} = (\text{numerical value}) \times (\text{unit})

where: the numerical value depends entirely on which unit you chose, while the physical quantity itself does not change — this is why 5 m5\ \text{m} and 500 cm500\ \text{cm} describe the identical length. The seven SI base units are:

QuantitySI base unitSymbol
Lengthmetrem
Masskilogramkg
Timeseconds
Electric currentampereA
Thermodynamic temperaturekelvinK
Amount of substancemolemol
Luminous intensitycandelacd

Derived and supplementary units. Every other unit — for velocity, force, energy, pressure — is a derived unit, built by combining base units according to the defining equation of that quantity. Velocity is length divided by time, so its unit is m/s\text{m/s}; force is mass times acceleration, so its unit (kg ⋅ m/s2\text{kg}\,\cdot\,\text{m/s}^2) is later named the newton. Two units historically kept in a separate "supplementary" class are the radian (plane angle) and steradian (solid angle); modern SI treats both as derived, dimensionless units, but they matter throughout rotational-motion and radiation formulae later in the course.

Prefixes for scale. Because measured quantities range from subatomic to cosmological, SI multiplies or divides a unit by an exact power of ten using standard prefixes, from atto (aa, 10−1810^{-18}) to tera (TT, 101210^{12}):

PrefixSymbolFactor
attoa10−1810^{-18}
femtof10−1510^{-15}
nanon10−910^{-9}
microµ10−610^{-6}
millim10−310^{-3}
kilok10310^{3}
megaM10610^{6}
gigaG10910^{9}
teraT101210^{12}

Each prefix is an exact multiplier, never an approximation — 1 km1\ \text{km} is exactly 1000 m1000\ \text{m}, not "roughly a thousand."

Special units for extreme scales. Beyond prefixed SI units, physics keeps a handful of named units convenient for particular size regimes:

  • 1 fermi=1 fm=10−15 m1\ \text{fermi} = 1\ \text{fm} = 10^{-15}\ \text{m} — nuclear sizes
  • 1 angstrom=1 A˚=10−10 m1\ \text{angstrom} = 1\ \text{Å} = 10^{-10}\ \text{m} — atomic sizes
  • 1 light year=9.46×1015 m1\ \text{light year} = 9.46\times10^{15}\ \text{m} — distance light covers in vacuum in one year
  • 1 astronomical unit (AU)=1.496×1011 m1\ \text{astronomical unit (AU)} = 1.496\times10^{11}\ \text{m} — mean Earth–Sun distance
  • 1 parsec=3.08×1016 m1\ \text{parsec} = 3.08\times10^{16}\ \text{m} — a stellar-distance unit, about 3.263.26 light years
  • 11 unified atomic mass unit (u)=1.66×10−27 kg(u) = 1.66\times10^{-27}\ \text{kg} — mass scale for atoms
Figure
A single horizontal logarithmic scale from ten to the minus fifteen metres to ten to the sixteen metres marking the fermi at nuclear size, the angstrom at atomic size, the metre at human size, the astronomical unit at planetary size, and the light year and parsec at stellar size
Length scales span thirty orders of magnitude fermi 10⁻¹⁵ m angstrom 10⁻¹⁰ m metre 10⁰ m astronomical unit 1.5×10¹¹ m light year 9.46×10¹⁵ m parsec 3.08×10¹⁶ m Nuclear, atomic, human, planetary and stellar scales all need different natural units
Derivation AConverting a distance from one special unit to another

The goal is to show, with nothing beyond dividing one definition by another, how any special length unit converts cleanly into any other once both are expressed in the common reference of metres, and to apply this method to turn the Earth–Sun distance into light years, which is the standard way ISC problems test whether you actually understand the special units rather than just memorising their names.

Step 1. Write both units in their SI definitions. The Earth–Sun distance is 1 AU=1.496×1011 m1\ \text{AU} = 1.496\times10^{11}\ \text{m}, and the light year is defined as 1 ly=9.46×1015 m1\ \text{ly} = 9.46\times10^{15}\ \text{m}. Both numbers are anchored to the same base unit, the metre, which is exactly why a direct conversion is possible.

Step 2. Set up the conversion as a ratio. To express 1 AU1\ \text{AU} in light years, divide the AU's metre value by the light year's metre value: 1 AU=1.496×1011 m9.46×1015 m/ly ly1\ \text{AU} = \dfrac{1.496\times10^{11}\ \text{m}}{9.46\times10^{15}\ \text{m/ly}}\ \text{ly}. The metre units cancel top and bottom, leaving a pure number of light years.

Step 3. Carry out the division. 1.496×10119.46×1015=1.58×10−5\dfrac{1.496\times10^{11}}{9.46\times10^{15}} = 1.58\times10^{-5}, so 1 AU=1.58×10−5 ly1\ \text{AU} = 1.58\times10^{-5}\ \text{ly}.

Step 4. Read the physical meaning. The Earth–Sun distance is only about sixteen-millionths of a light year, confirming that the light year is a unit suited to interstellar distances, while the AU is suited to distances within a solar system — using a light year to measure a planet's orbit would give an inconveniently tiny, hard-to-read number, which is precisely the "convenient size" requirement a good unit must satisfy.

Worked example

Problem. A hydrogen atom has a nuclear radius of about 1.2 fm1.2\ \text{fm} and an atomic radius of about 0.53 A˚0.53\ \text{Å}. Find the ratio of atomic radius to nuclear radius.

Step 1. Convert both radii to the same unit, metres, since fermi and angstrom are defined against different powers of ten and cannot be compared directly. 1.2 fm=1.2×10−15 m1.2\ \text{fm} = 1.2\times10^{-15}\ \text{m} and 0.53 A˚=0.53×10−10 m=5.3×10−11 m0.53\ \text{Å} = 0.53\times10^{-10}\ \text{m} = 5.3\times10^{-11}\ \text{m}.

Step 2. Divide atomic radius by nuclear radius: atomic radiusnuclear radius=5.3×10−111.2×10−15≈4.4×104\dfrac{\text{atomic radius}}{\text{nuclear radius}} = \dfrac{5.3\times10^{-11}}{1.2\times10^{-15}} \approx 4.4\times10^{4}.

Answer: the atom's radius is roughly 44,000 times its nucleus's radius — which is why an atom is mostly empty space, with almost all its mass packed into a nucleus occupying a tiny fraction of its volume.

Competitive stretch

How many astronomical units fit inside one parsec? Using 1 parsec=3.08×1016 m1\ \text{parsec} = 3.08\times10^{16}\ \text{m} and 1 AU=1.496×1011 m1\ \text{AU} = 1.496\times10^{11}\ \text{m}: 3.08×10161.496×1011≈2.06×105\dfrac{3.08\times10^{16}}{1.496\times10^{11}} \approx 2.06\times10^{5}. A parsec is about 206,000206{,}000 astronomical units — one more reminder that each special unit exists because it keeps the numbers of its own domain, from nuclear to galactic, close to a convenient single digit times a small power of ten.

Common traps

  • Confusing base units with derived units — only the seven listed quantities have base units; force, energy, pressure, velocity and everything else is derived from them.
  • Treating a prefix like kilo or milli as an approximate factor rather than an exact power of ten — 1 km1\ \text{km} is exactly 1000 m1000\ \text{m}, never "about a thousand."
  • Mixing unit systems inside one calculation, such as using centimetres for length while keeping seconds and kilograms for the rest — convert everything to one consistent system, usually SI, before calculating.
  • Dismissing the radian and steradian as unimportant because they seem dimensionless — they are supplementary units used consistently in later rotational-motion and radiation formulae, and dropping them silently causes unit-mismatch errors.

Ask the tutor: want to practice converting between more of these special units, like turning a parsec into light years or a mass in atomic mass units into kilograms?

Why do we need both SI prefixes and separate special units like the fermi and the light year

Prefixes just rescale the same base unit by an exact power of ten, so a nanometre is still fundamentally the metre. Special units like the fermi, angstrom, light year, astronomical unit and parsec exist because certain domains — nuclear physics, atomic physics, astronomy — repeatedly need one particular scale, and giving that scale its own name avoids writing long strings of prefixed metres every time. Both tools solve the same problem, convenient size, in slightly different ways.

Is the radian really a unit, since angle seems like a pure number

Yes, historically it was kept in a separate supplementary class precisely because an angle in radians is the ratio of arc length to radius, both lengths, so the radian looks dimensionless. Modern SI treats it as a derived unit for exactly that reason, but you should still write it explicitly in formulae involving angular velocity or angular momentum, because mixing radians with degrees silently in a formula is a common source of wrong answers.

How do I decide which special unit to use when a problem gives a distance in metres

Look at the order of magnitude. Distances around 10−15 m10^{-15}\ \text{m} belong to nuclei, so use the fermi; around 10−10 m10^{-10}\ \text{m} belong to atoms, so use the angstrom; around 1011 m10^{11}\ \text{m} belong to planetary distances, so use the astronomical unit; and distances beyond 1015 m10^{15}\ \text{m} belong to stars, so use the light year or parsec. Matching the unit to the scale is exactly the "convenient size" property a good unit must have, and examiners often reward recognising the right unit as much as the arithmetic.

Before this

Where this leads