The magnetic field of a plane electromagnetic wave is where is the speed of light

PHYSICS · Single correct · CBSE · Physics · Electromagnetic Waves · Electromagnetic Waves

Problem

The magnetic field of a plane electromagnetic wave is B⃗=3×10−8sin⁡[200π(y+ct)]i^ T\vec{B} = 3 \times 10^{-8} \sin[200\pi(y + ct)] \hat{i} \text{ T} where c=3×108 ms−1c = 3 \times 10^8 \text{ ms}^{-1} is the speed of light. The corresponding electric field is : (1) E⃗=9sin⁡[200π(y+ct)]k^ V/m\vec{E} = 9 \sin[200\pi(y + ct)] \hat{k} \text{ V/m} (2) E⃗=−10−6sin⁡[200π(y+ct)]k^ V/m\vec{E} = -10^{-6} \sin[200\pi(y + ct)] \hat{k} \text{ V/m} (3) E⃗=3×10−8sin⁡[200π(y+ct)]k^ V/m\vec{E} = 3 \times 10^{-8} \sin[200\pi(y + ct)] \hat{k} \text{ V/m} (4) E⃗=−9sin⁡[200π(y+ct)]k^ V/m\vec{E} = -9 \sin[200\pi(y + ct)] \hat{k} \text{ V/m}

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