In a double-slit experiment the slit width equals one-half of the center-to-center…

PHYSICS · Single correct · CBSE · Physics · Wave Optics · Wave Optics

Problem

In a double-slit experiment the slit width aa equals one-half of the center-to-center separation dd between the slits. Monochromatic light of wavelength λ\lambda produces a series of interference maxima on a distant screen, but the m=2m=2 bright fringe is not observed. Which of the following best explains the absence of this fringe? (a) The m=2m=2 bright fringe is too close to the central maximum to be resolved by the detector. (b) At the position of the m=2m=2 fringe the path difference equals 2.5λ2.5\lambda, leading to incomplete constructive interference and hence little or no intensity. (c) For a=12da=\tfrac12 d, the m=2m=2 interference maximum occurs at the same angle as the first minimum of the single-slit diffraction pattern, so its intensity is effectively zero. (d) Because each slit is very narrow, the diffraction envelope is so broad that higher-order maxima like m=2m=2 overlap and blend into the background, so the fringe is not observed.

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