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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
sin
3
x
sin
x
d
x
=
\int\frac{\sin3x}{\sin x}\,dx=
∫
s
i
n
x
s
i
n
3
x
d
x
=
(a)
x
+
sin
2
x
+
C
x+\sin2x+C
x
+
sin
2
x
+
C
(b)
3
x
+
sin
2
x
+
C
3x+\sin2x+C
3
x
+
sin
2
x
+
C
(c)
3
x
+
sin
2
x
+
C
3x+\sin^2x+C
3
x
+
sin
2
x
+
C
(d) None of these
Related theory
Antiderivatives
Trigonometric Identities
Trigonometric Functions
Integration Techniques
Standard trigonometric integrals
Integration using trigonometric identities
Integrals
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