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MATHEMATICS · Single correct · CBSE · Mathematics · Trigonometric Functions · Trigonometric Functions

Problem

If 2cos⁡a=cos⁡b+cos⁡3b\sqrt{2}\cos a=\cos b+\cos^3b and 2sin⁡a=sin⁡b−sin⁡3b\sqrt{2}\sin a=\sin b-\sin^3b, then sin⁡(a−b)=\sin(a-b)= (1) ±1\pm1 (2) ±12\pm\frac{1}{2} (3) ±13\pm\frac{1}{3} (4) ±14\pm\frac{1}{4}

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