Prove that A + 2A + 4A + 5A A + 2A + 4A + 5A = 3A.

MATHEMATICS · Subjective · CBSE · Mathematics · Trigonometric Functions · Trigonometric Functions

Problem

Prove that sin⁡A+sin⁡2A+sin⁡4A+sin⁡5Acos⁡A+cos⁡2A+cos⁡4A+cos⁡5A=tan⁡3A.\frac{\sin A + \sin 2A + \sin 4A + \sin 5A}{\cos A + \cos 2A + \cos 4A + \cos 5A} = \tan 3A.

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