The answers are in Chapter 24.

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Problem

The answers are in Chapter 24. (A) 112ln⁡∣4x3+1∣+C\frac{1}{12} \ln \left|4 x^{3}+1\right|+C (B) ln⁡∣4x3+1∣+C\quad \ln \left|4 x^{3}+1\right|+C (C) −1(4x3+1)2+C\frac{-1}{\left(4 x^{3}+1\right)^{2}}+C (D) x3(4x3+1)2+C\frac{x^{3}}{\left(4 x^{3}+1\right)^{2}}+C

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