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CBSE
MATHEMATICS · Single correct · CBSE · Mathematics · Integrals · Integrals
Problem
∫
1
1
−
e
2
x
d
x
=
\int\frac{1}{\sqrt{1-e^{2x}}}\,dx=
∫
1
−
e
2
x
1
d
x
=
(a)
x
−
log
[
1
+
1
−
e
2
x
]
+
C
x-\log\left[1+\sqrt{1-e^{2x}}\right]+C
x
−
lo
g
[
1
+
1
−
e
2
x
]
+
C
(b)
x
+
log
[
1
+
1
−
e
2
x
]
+
C
x+\log\left[1+\sqrt{1-e^{2x}}\right]+C
x
+
lo
g
[
1
+
1
−
e
2
x
]
+
C
(c)
log
[
1
+
1
−
e
2
x
]
−
x
+
C
\log\left[1+\sqrt{1-e^{2x}}\right]-x+C
lo
g
[
1
+
1
−
e
2
x
]
−
x
+
C
(d) None of these
Related theory
Antiderivatives
Integration Techniques
Integration by Substitution
Integrals
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