Evaluate , and is independent of . Hence, show _ 0 ^ 1 x^k (1-x)^ n-k dx = 1 ^n C_k…

MATHEMATICS · Subjective · AP · Calculus AB · Integration and Accumulation of Change · Integration and Accumulation of Change

Problem

Evaluate ∫01(tx+1−x)ndx\int_{0}^{1} (tx + 1 - x)^n dx , n∈Nn \in N and tt is independent of xx . Hence, show ∫01xk(1−x)n−kdx=1nCk(n+1).\int_{0}^{1} x^k (1-x)^{n-k} dx = \frac{1}{{}^n C_k (n+1)}.

Related theory

Browse the problem library