CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Trigonometric Functions · Trigonometric Functions

Problem

sin⁡3θ cos⁡θ\sin 3\theta\,\cos \theta is equal to (a) 12 [sin⁡(4θ)−sin⁡(2θ)]\dfrac{1}{2}\,[\sin(4\theta)-\sin(2\theta)] (b) 12 [cos⁡(4θ)+cos⁡(2θ)]\dfrac{1}{2}\,[\cos(4\theta)+\cos(2\theta)] (c) 12 [sin⁡(4θ)+sin⁡(2θ)]\dfrac{1}{2}\,[\sin(4\theta)+\sin(2\theta)] (d) 12 sin⁡(4θ)\dfrac{1}{2}\,\sin(4\theta)

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