CBSE

MATHEMATICS · Single correct · CBSE · Mathematics · Trigonometric Functions · Trigonometric Functions

Problem

Solve cos⁡2θ=sin⁡θ\cos 2\theta = \sin\theta for θ∈[0,2π)\theta\in[0,2\pi). (a) {π3, 2π3, 3π2}\Big\{\dfrac{\pi}{3},\,\dfrac{2\pi}{3},\,\dfrac{3\pi}{2}\Big\} (b) {π6, 5π6, 3π2}\Big\{\dfrac{\pi}{6},\,\dfrac{5\pi}{6},\,\dfrac{3\pi}{2}\Big\} (c) {π6, 5π6}\Big\{\dfrac{\pi}{6},\,\dfrac{5\pi}{6}\Big\} (d) {π2, 7π6, 11π6}\Big\{\dfrac{\pi}{2},\,\dfrac{7\pi}{6},\,\dfrac{11\pi}{6}\Big\}

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